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2x^2-14x=156
We move all terms to the left:
2x^2-14x-(156)=0
a = 2; b = -14; c = -156;
Δ = b2-4ac
Δ = -142-4·2·(-156)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-38}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+38}{2*2}=\frac{52}{4} =13 $
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